Math, asked by rozy50, 7 months ago

find the value of K , in quadratic equation 9x2-Kx+16=0 if roots are equal ​

Answers

Answered by krishgupta01509
0

Answer:

9x2-kx+16 =0

On comparing with ax2 + bx+c =0

a= 9, b= -k and c= 16

D = 0

formula -

b2 -4ac= 0

(-k)2 -4(9)(16) = 0

= k2 - 576= 0

= k = √576

= k = 24

I hope it helps you

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