Question

find the value of k in such a linear equation7kx+6y-1=0 and 2x+10-7=0 represent the pair of parallel lines

Answer 1

$\frac{a1}{a2} = \frac{b1}{b2} \: = \frac{c1}{c2} \\ when \: lines \: are \: parallel \\ so \: put \: the \: values \\ \frac{7k}{2} = \frac{6}{10} \\ now \: cross \: multiply \\ 70k = 12 \\ k = \frac{12}{70} \\ k = \frac{6}{35}$

Answer 2

refer to the attachment.....