find the value of k in the following polynomials
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Hey friend ..!! here's your answer
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if x = 3/2
2x^2 + kx - 12 =0
put the value of x in polynomial
2(3/2)^2 + k(3/2) -12 =0
18/4 + 3k / 2 - 12 =0
18 + 6k -12 =0
6k + 6 = 0
6k = -6
k = -1
So that the value of k is -1
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#Hope its help you dear#
☺
_________________________
if x = 3/2
2x^2 + kx - 12 =0
put the value of x in polynomial
2(3/2)^2 + k(3/2) -12 =0
18/4 + 3k / 2 - 12 =0
18 + 6k -12 =0
6k + 6 = 0
6k = -6
k = -1
So that the value of k is -1
____________________
#Hope its help you dear#
☺
Anonymous:
hope u understand....
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