Question

find the value of k in the quadratic equation 9 x square - kx + 16 =0. if roots are equal​

Answer 1

Answer:

k=24

Step-by-step explanation:

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Answer 2

Answer:

Since roots of the equation are real and equal.

There fore, Discriminant = 0

Here a =9, b = - k, c = 16.

Now, D = 0

${b}^{?} - 4ac = 0 \\ {( - k)}^{2} - 4 \times 9 \times 16 = 0 \\ {k}^{2} = 4 \times 9 \times 16 = 576\\ k = 24 \: or \: - 24$