Find the value of k in the quadratic eqution 3xsquqre-kroot3x+4=0 has equalroots
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Answered by
1
Equation has equal roots means D=0
D=b²-4ac
0=( - k√3)² - 4(3)(4)
0=3k²-48
48 = 3k²
16 =k²
√16=k
4=k
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D=b²-4ac
0=( - k√3)² - 4(3)(4)
0=3k²-48
48 = 3k²
16 =k²
√16=k
4=k
I hope it helps you
please mark it as brainlist
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Answered by
1
comparing 3x^2-k√3+4=0 by ax^2+bx+c=0
we get,
a=3, b=-k√3,c=4
b^2-4ac
=(-k√3)-4×3×4
=3k^2-48
3k^2=48
k^2=48/3
k=√16
k=4
the value of k =4
we get,
a=3, b=-k√3,c=4
b^2-4ac
=(-k√3)-4×3×4
=3k^2-48
3k^2=48
k^2=48/3
k=√16
k=4
the value of k =4
not asking the value of x
find value of k
okayyyy
again i do
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