Question

Find the value of k in X²-(k+4)x+2x+5=0​

Answer 1

Answer:

Step-by-step explanation:

your answer

For any quadratic equation ax^2 +2bx +c =0, to have equal roots, it must satisfy the , a= c conditio.

So, in above question,

2 =-k+5

K =3

We can check whether the answer is correct or not, the actual equation was,

2x^2-4x+2=0

2 (x^2-2x+1)=0

(x-1)^2 =0

x=1

This shows the roots are 1 and 1.

Hence proved….

Answer 2

Answer:

x²-(k+4)x+2x+5=0

since the value of x is not given .........when x= 1

1 - ( k + 4 ) + 2 + 5 = 0

8 - ( k + 4 ) = 0

8 = ( k + 4 )

8 - 4 = k

4 = k ( answer )

if the answer is useful pls mark as brainliest....pls and  do follow meee