Question

Find the value of 'k' is the product
zeroes of
the polynomial kx² + 7x +10 is 5

​

Answer 1

Answer:

Step-by-step explanation:

ANSWER:-

We need to find the value of k in polynomial $kx^{2} + 7x +10$, given product of zeroes as 5.

So, we know that let the zeroes to be taken as $\alpha \ and\ \beta$.

$\alpha\times\beta=\frac{c}{a}$

• Where a is k
• Where b is 7
• Where c is 10

We are already given that

$\boxed{\alpha\times\beta=5}$, so

$5 = \frac{10}{k}$

$\frac{1}{k}=\frac{1}{2}$

$\boxed{\boxed{k=2}}$.

Things to Remember:-

• The following are for highest degree 2 as polynomial or Binomial.

$\alpha+\beta=\frac{-b}{a}$

$\alpha\times\beta=\frac{c}{a}$

• For cubic Polynomial,

$\alpha+\beta+\gamma = \frac{-b}{a}$

$\alpha\beta+\beta\gamma+\gamma\alpha = \frac{c}{a}$

$\alpha\beta\gamma = \frac{-d}{a}$

For a polynomial example $3x^{3}+4x^{2}-2x+1$,

• a is 3
• b is 4
• c is -2
• And d is 1.

Answer 2

Answer:

We need to find the value of k in polynomial , given product of zeroes as 5.

So, we know that let the zeroes to be taken as .

Where a is k

Where b is 7

Where c is 10

Step-by-step explanation: