Question

Find the value of K of equatipn kx(x-3)+9 so that it has two equal roots​

Answer 1

Kx(x-3)+9=0 has two equal roots.

The equation has two equal roots which means discriminant is zero.

i.e. k=0,k=4.

Reject k=0.

The value of k is 4.

hope it helps you

please follow and mark as brainliest

Answer 2

Answer: The value of k is 4

Step-by-step explanation:

Given : Equation Kx(x-3)+9=0 has two equal roots.

To find : The value of k ?

Solution :

The equation is Kx^2-3kx+9=0

On comparing with quadratic equation ax^2+bx+c=0

Here, a=k, b=-3k and c=9

The equation has two equal roots which means discriminant is zero.

i.e. b^2-4ac=0

(-3k)^2-4(k)(9)=0

9k^2-36k=0

9k(k-4)=0

Either 9k=0 or k-4=0

i.e. k=0,k=4.

Reject k=0.

The value of k is 4.

HOPE U ARE SATISFIED..

HAPPY TO HELP YOU..

Please mark me as the BRAINLIEST..