Question

Find the value of k, points A, B and C are collinear.
A(0,4),B(3, - 2), C(k, k+3).

Answer 1

Step-by-step explanation:

1/2[0(-2-k-3)+3(k+3-4)+k(4+2)=0

1/2[3(k-1)+6k]=0

1/2[3k-3+6k]

1/2[9k-3]=0

3/2(3k-1)=0

3k-1=0

k=1/3