Question

Find the value of k so that (9) k+1 × (27) 2 = (3)10​

Answer 1

Given: $(9) k+1\times(27) 2 = (3)10$

We have to find the value of$x$.

• By using the concept of equation shifting, we are solving the above equation.  
• For this, we will separate the variables on one side and the constant on another side.
• Then, we will simplify the equation.

We are solving in the following way:

We have,

$(9) k+1\times(27) 2 = (3)10$

Solving the above equation further we get,

$=>9k+1\times54=30\\=>9k+54=30\\=>9k=30-54\\=>9k=-24\\\\=>k=\frac{-24}{9} \\\\=>k=\frac{-8}{3}$

Hence, the value of$k$ is$\frac{-8}{3}$.

Answer 2

Answer:

The value of $k$ is $-0.938$.

Step-by-step explanation:

Given : The expression is $9(k+1)*27*2=3*10$

To find : The value of $k$.

Solution :

• The given expression is $9(k+1)*27*2=3*10$
• We have to find the value of $k$.
• To find the value of $k$, use the BODMAS rule.
• It states that,  while solving any algebraic equation, we have to first solve the B-Bracket, O-Order, D-Division, M-Multiplication, A-Addition and S-Subtraction.

• The given expression is,

       $9(k+1)*27*2=3*10$

           ∴ $(9k+9)*54 =30$

              ∴ $486k+486=30$

              ∴ $486(k+1)=30$

• Transpose $486$ to other side, we get

                  ∴ $k+1=\frac{30}{486}$

                  ∴ $k = \frac{30}{486} -1$

                    ∴ $k=\frac{30-486}{486}$      

                      ∴ $k=\frac{-456}{486}$

                        ∴ $k=-0.938$

• ∴ The value of $k$ is $-0.938$.