Question

Find the value of k so that each of the following equations may be x = 1, y = 1 as the solution.

1) kx-2y=10, 2) 5x +2ky = 3k, 3) x – y = k, 4) 6x +2ky = 3k

Answer 1

Answer:

1) k=12

2)k=5

3)k=0

4)k=6