Question

Find the value of K, so that the difference of the roots of x - 5x + 3 (k
- 1) is 11.​

Answer 1

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Answer 2

Answer:

hey mate...is it,

x-5x+3(k-1)=0

or

x^2-5x-3(k-1)=0 ❓❓❓

if your question is...x^2-5x-3(k-1)=0

then the answer is...k=(-7)

Explanation:

x² - 5x +3(k - 1 ) = 0

Let the root be a and b respectively .

Now ,

given that difference of root = 11

Let a > b

So ,

a - b = 11 –––( i )

And ,

We know that ,

sum of roots = -( b ) / a

so , a + b = - ( -5 ) / 1

=> a + b = 5 ––– ( ii )

Now , adding eq ( i )and ( ii ) , we get

a - b + a + b = 11 + 5

=> 2a = 16

=> a = 8

So ,

8 - b = 11

=> - b = 3

=> b = -3 .

Now ,

We know that ,

product of zeros = c / a

So ,

a * b = c / a

=> 8 * ( - 3 ) = 3 ( k - 1 ) / 1

=> - 24 = 3 ( k - 1 )

=> -8 = k - 1

=> k - 1 = -8

=> k = -8 + 1

=> k = -7

So ,

required value of k = (-7)

You can check it by putting the value of k in the equation .

I hope it may be helpful for you.

Thank you!