Question

Find the value of k, so that the following system of equations has a unique solution .
13. x+2y=5; 3x + ky +15=0.
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Answer 1

Answer:

3x + 3x + 6y + ky = 0

calculate with the other

Answer 2

Step-by-step explanation:

x+2y=5

3x+ky+15=0

a1= 1 b1= 3 c1= -5

a2= 2 b2= k c2= 15

For unique solutions

a1/a2= b1/b2 not equal to c1/c2

1/2= 3/k not equal to-1/3

So, by cross multiplication we get k= 6