Question

Median of the values of
sec60°, cot45º, sin 90° and cos 60°?​

Answer 1

Answer:

1

Step-by-step explanation:

sec 60=2/$\sqrt{3\\}$=1.15

cot45=1

sin90=1

cos 60=$\sqrt{3}$/2=0.867

in ascending order;0.866,1,1,1.15

No of observation(N)=4

Now

we know

median= [(N/2)+{(N/2)+1}]/2

            =[(4/2)+{(4/2)+1}]/2

            =[2nd+3rd]item/2

             =[1+1]/2

              =2/2

              =1