Question

Find the value of k so that the following system of linear equations has no solution
3x-y-5=0
6x-2y+k=0
(A)k=-10
(B)k=3
(C)k=-9
(D)k=7​

Answer 1

Solution:-

given:-

=> 3x-y-5=0

=> 6x-2y+k=0

now,

=> 3x - y - 5

=> 3x - y = 5 ..(1)

so,

=> 6x - 2y + k = 0

=> 2(3x - y ) + k = 0

we by eq.(1)

3x - y = 5

so,

=> 2(5) + k = 0

=> 10 + k = 0

=> k = - 10

so, Answer is k = - 10.

(A) k = -10

i hope it helps you.