Question

Find the value of k so that the functioning system has no solution 3x-y-5,6x-2y+k

Answer 1

The value of k = 10.

Step-by-step explanation:

Given two equations, 3x – y – 5 = 0 (i.e) 3x - y = 5 …. (1)

6x - 2y +k = 0 (i.e) 6x - 2y = -k …. (2)

Divide equation (2) by 2, it becomes, 3x – y = \left(\frac{k}{2}\right) … (3)

From equation (1) and (3) LHS are equal, hence consider RHS

\left(\frac{k}{2}\right) = 5, k = 10 for the problem to have solution,

Condition for no solution be k ≠ ,-10.

Answer 2

Step-by-step explanation:

3x - y - 5 = 0

6x - 2y + k = 0

a1 = 3, b1 = -1, c1 = -5

a2 = 6, b2 = -2, c2 = k

in case of no solution,

a1/a2 = b1/b2 ≠ c1/c2

3/6 = -1/-2 ≠ -5/k

1/2 = 1/2 ≠ -5/k

K ≠ -10