Question

Find the value of k so that the pair of equations x+2y=15 and 3x+ky+15=0 has unique solution?​

Answer 1

Step-by-step explanation:

arrange these numbers both in ascending and descending oder

Answer 2

Answer:

Value of k can't be 6 .

Step-by-step explanation:

Condition for unique solution,

$\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$

x + 2y = 15 ----- (i)

3x + ky + 15 = 0 ----- (ii)

$\frac{1}{3} \neq \frac{2}{k} \\\\k\neq 2*3\\\\k\neq 6$

Hence, K can't be 6 .