Find the value of k so that the polynomial has equal roots
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As you have not specified the equation , here is an eg: of the method to solve such a question :-
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Question - Find the value of k for which the given equation (k+4)x² + (k+1)x+1=0 has equal roots.
Solution :-(k + 4)x² + (k + 1)x + 1 = 0
a = (k +4) , b = (k +1) , c = 1
As the equation has equal roots ,
b² - 4ac = 0
(k+1)² - 4(k+4) (1) = 0
k² + 2k + 1 - 4k -16 = 0
k² - 2k -15 = 0
(k - 5)(k + 3) = 0
k = 5 , k = -3
the values of k are 5 and -3
As you have not specified the equation , here is an eg: of the method to solve such a question :-
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Question - Find the value of k for which the given equation (k+4)x² + (k+1)x+1=0 has equal roots.
Solution :-(k + 4)x² + (k + 1)x + 1 = 0
a = (k +4) , b = (k +1) , c = 1
As the equation has equal roots ,
b² - 4ac = 0
(k+1)² - 4(k+4) (1) = 0
k² + 2k + 1 - 4k -16 = 0
k² - 2k -15 = 0
(k - 5)(k + 3) = 0
k = 5 , k = -3
the values of k are 5 and -3
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