Question

find the value of k so that the quadratic equation 3 X square + 2 k x + 27 is equal to zero has real and equal roots...​

Answer 1

Answer:

$k = 9$

Step-by-step explanation:

$3 {x}^{2} + 2kx + 27$

$if \: the \: equation \: has \: real \: and</p><p>equal\:$ $roots \: it \: should \: satisfy$

${b}^{2} - 4ac = 0$

${(2k)}^{2} - 4(3)(27) = 0$

$4 {k}^{2} - 324=0$

$4 {k}^{2} = 324$

${k}^{2} = 81$

$k = 9$

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Answer 2

Answer:

hope it is clear....