integrate
[x+1/x]^3
please solve it fast
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Answer:
Step-by-step explanation:I think you mean ∫[x+(1/x)]³ dx=∫f(x)dx ,for which you have no choice but to expand the INTEGRAND in the smart way...
① f(x)=[x+(1/x)]³
=[(x²+1)/x]³
=(1+x²)³/x³
={1+3x²+3x^4+x^6}/x³
=x^(-3)+3[x^(-1)]+3x+x³
② ∫f(x)dx
=-½(1/x²)+3㏑|x|+3(x²/2)+¼x^4+C
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