Find the value of k so that the quadratic equation 3x²-kx+27=0 has equal root
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Step-by-step explanation:
3x-kx+27=0
For equal roots
D =0
=> b^2 - 4ac =0
=> (-k)^2 - 4*3*27=0
=> k^2 - 324 =0
=> k^2 = 324
=> k= /sqrt(324)
=> k = +18 or k= - 18
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