Question

Find the value of k so that the sum of yhe roots of the quadratic equation. (k-1)x^2+(2k+1)x-9=0 is equal to the product of the roots

Answer 1

We know sum of the quadratic equations can be given by (-b/a) and product by (c/a)

Hence for them to be equal,

[-(2k+1)]/(k-1) = -9/(k-1)

2k+1=9

2k=8

k=4

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Answer 2

(k-1)^2+(2k+1)×9=0
or,k^2-1+18k+9=0
or,k^2+18k+8 = 0
by quadratic equation :-
D = b^2-4ac
or,0=18^2- (4k×8)
or,324-32k =0
or,324=324k
or,324÷32=k
or,10.12=k