Find the value of k so that the system has no solution 3x-y-5=0 and 6x-2y-k=0
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For no solution, ratio of coefficients of x & y should not be equal to ratio of constant terms
→1/2≠5/k
k≠10
so k can take any real value except 10
→1/2≠5/k
k≠10
so k can take any real value except 10
MayankSoni:
Sorry for delay
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