Question

Find the value of 'k' so that the zeroes of the quadratic polynomial 3x²-kx+14 are in the ratio 7:6

Answer 1

Heya !!



Let zeroes are 7X and 6X.



P(X ) = 3X² - KX + 14



Here,

A = 3 , B = -K and C = 14



Therefore,



Product of zeroes = C/A



7X × 6X = 14/3



42X² = 14/3



X² = 14 × 42/3


X² = ( 14 × 14 )



X = ✓196 = 14




First zero = 7X = 7 × 14 = 98

And,


Second zero = 6X = 6 × 14 = 84.



Sum of zeroes = -B/A



98 + 84 = -(-K)/3


182 = K/3



K = 182 × 3


K = 546.