Question

find the value of k so that they have two equal roots 2 X square + kx + 3 is equal to zero​

Answer 1

Answer:

$k = 2 \sqrt{6} \: \: \: \: \: \: \: k = - 2 \sqrt{6}$

Step-by-step explanation:

$2 {x}^{2} + kx + 3 = 0 \\ \\ for \: equal \: roots \\ \\ discriminant = 0 \\ \\ {b}^{2} - 4ac = 0 \\ \\ {k}^{2} - 4(2)(3) = 0 \\ \\ { {k}^{2} - 24 = 0}^{} \\ \\ k = 2 \sqrt{6} \: \: \: \: \: \: \: k = - 2 \sqrt{6}$