Find the value of k, so that ( x2 – 2x + k ) leaves the remainder 3 when divided
By x+1 is
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p(x) = x² - 2x + k
According to the Question:
p(-1) = 3
So,
==> (-1)² - 2(-1) + k = 3
==> 1 + 2 + k = 3
==> 3 + k = 3
==> k = 3 - 3
==> k = 0
Hence, value of k should be 0 to get remainder 3 when divided by (x + 1)
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