find the value of k so the equation kx^2-6x+8=0 will have equal root
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Answer:
Amswer
Step-by-step explanation:
The condition for a quadratic equation
ax3+bx+e=0 to have equal roots, is
b2-4ac=0
For the given equation kx2-6x-2=0
b2-4ac=(-6)2-4k (-2)=0
36+8k =0
8k=-36
k=-36_8=-9_2
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