Question

Find the value of k such that the polynomial-(x+ 6)x + 2(2k - 1) has sum of its zeros epal to of their product

Answer 1

Answer:

$sum \: of \: zeroes = product \: of \: zeroes \\ \frac{ - b}{a} = \frac{c}{a} \\ \: - b = c \\ - ( - 6) = 4k - 2 \\ 6 = 4k - 2 \\ 4k = 8 \\ \bold{k = 2} \\ hope \: it \: helps \: u....$

Answer 2

Answer:

k=2

Explanation:

let the polynomial be

-(x+6)x + 2(2k-1)

the general form of polynomial is

x² + 6x -2k+2

now acq to questions

a and b are zeroes

a+b = ab

-6/1=-2k+2/1

-2k+2=-6

-2k. = -4

k=2