Question

Find the value of k such that the quadratic equation : x(x-2k) + 6=0,has real and equal roots.

Answer 1

Heya Friend!!

Here's ur ans with solution :-

☣ As we know if the quadratic equation has real and equal roots then it's discriminant should be equal to zero.

that is :- D = 0

x( x - 2k ) + 6 = 0

x² - 2kx + 6 = 0


From the equation,

a = 1

b = -2k

c = 6

And,

D = b²- 4ac

0 = (-2k)² - 4 × 1 × 6

0 = 4k² -24

24 = 4k²

24/4 = k²

6 = k²

±√6 = k

@Altaf

Answer 2

Answer:

a=1

b=-2k

c=6

d=b²-4ac

0=(-2k)²

0=4k²-4x1x6

0=4k²-24

24=4k²

24/4=k²

6=k²

± ✓6=k