Question

Find the value of k Such that the quadratic polynomial x²-(k+6)x+2(k+1) has some of the zeros Is half of their product

Answer 1

Step-by-step explanation:

Let x and y be the zeroes.

x + y = xy/2

So,

-

$\frac{ - b}{a} = \frac{c}{a} \times \frac{1}{2}$

-2b = c

2(-(-(k+6))) = 2(k+1)

k + 6 = k + 1

6 = 1

So, the question is wrong.