Question

Find the value of k such that the quadratic polynomial x2-(x+6)x+2(2k-1) has sum of its zeros equals to half of their product

Answer 1

Step-by-step explanation:

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Answer 2

Given :  $x^2-(k+6)x+2(2k-1)$

It has sum of its zeroes equal to half of their product.

To find :  the value of k.

Solution:

As we know that

Sum of its zeroes = $k+6$

Product of its zeroes = $2(2k-1)$

According to question, it becomes :

Sum of zeroes = $\dfrac{1}{2}\times$ Product of their zeroes

So, it becomes,

$k+6=\dfrac{1}{2}\times 2(2k-1)\\\\k+6=2k-1\\\\6+1=2k-k\\\\7=k$

Hence, the value of k is 7.