Question

find the value of k such that the sum of square of zeroes of polynomial x²-8x+k is 40​

Answer 1

polynomial is x²-8x+k

$\alpha + \beta = 8$

$\alpha \beta = k$

by, A.T.Q,

alpha² + beta² = 40,

(alpha+beta)² - 2 alpha*beta = 40

( 8)² - 2*k = 40

64 - 2k = 40

-2k = 40-64

-2k = -24

2k = 24

k = 12.

hence, hope it helps u..

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