find the value of k such that the system of linear equation 2x + 4 Y + 7 equal to zero and 3 x minus K Y + 1 equal to zero has no solution
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no solution in common will mean that a1/a2 = b1/b2 and not = c1/c2
a1/a2 = 2/3
b1/b2 = 4/k
2/3 = 4/k
2k = 4*3 = 12
k =12/2 = 6
a1/a2 = 2/3
b1/b2 = 4/k
2/3 = 4/k
2k = 4*3 = 12
k =12/2 = 6
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