find the value of k where 2x-1 is a factor of 6x²+kx-2
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value of k is 1 is correct answer
pankaj184:
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Given f(x) = 6x^2 + kx - 2.
By Remainder theorem, we get
2x - 1 = 0
2x = 1
x = 1/2.
According to remainder theorem f(1/2) = 0, we get
f(1/2) = 6(1/2)^2 + k(1/2) - 2 = 0
= 6 * 1/4 + k/2 - 2 = 0
= 6/4 + k/2 - 2 = 0
= 6/4 - 2 + k/2 = 0
= -2/4 + k/2 = 0
= -1/2 + k/2 = 0
k/2 = 1/2
k = 1.
verification:
6(1/2)^2 + 1 * 1/2 - 2 = 0
6/4 + 1/2 - 2 = 0
3/2 - 3/2 = 0
0 = 0
Hope this helps!
By Remainder theorem, we get
2x - 1 = 0
2x = 1
x = 1/2.
According to remainder theorem f(1/2) = 0, we get
f(1/2) = 6(1/2)^2 + k(1/2) - 2 = 0
= 6 * 1/4 + k/2 - 2 = 0
= 6/4 + k/2 - 2 = 0
= 6/4 - 2 + k/2 = 0
= -2/4 + k/2 = 0
= -1/2 + k/2 = 0
k/2 = 1/2
k = 1.
verification:
6(1/2)^2 + 1 * 1/2 - 2 = 0
6/4 + 1/2 - 2 = 0
3/2 - 3/2 = 0
0 = 0
Hope this helps!
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