Question

find the value of k , where 31 K2 divisible by 6​

Answer 1

Answer:

K = 3 or 6.

Step-by-step explanation:

Given,

31K2 divisible by 6

Divisibility Rule of 6: If a number is exactly divisible by 6 it should be divisible by both 2 and 3.

31K2 is exactly divisible by 2, bcoz units place is 2

So, 31K2 must be divisible by 3

=> 3+1+K+2

=> 6+K

nearest Multiple is 9

So,

=> K = 9-6

=> K = 3

Here K can be 3,6.....So as the first preference

K = 3

=> 36K2 = 3632.

Hope it helps you....

Answer 2

Answer:

Given, 31k2 is divisible by 6. Then, it is also divisible by 2 and 3 both.

Now, 31K2 is divisible by 3, sum of its digits is a multiple of 3.

i.e. 3+ 1 + k + 2 = 0, 3, 6, 9,12,…

=> k+ 6 = 0, 3,6, 9,12

=> k = 0 or 3, 6, 9