Question

find the value of k x²-2(k+1)x+k²=0. please ans fast in hurry
​

Answer 1

Answer:

If we take the quadratic formula,

x=−b+−b2−4ac√2a

α=−b+b2−4ac√2a

β=−b−b2−4ac√2a

The only possibility for α=β is when b2−4ac=0 or just b2=4ac .

When b2−4ac=0

α=−b2a

β=−b2a

They are equal!

So, a=1,b=2(k+1),c=k2

4ac=4k2,b2=4k2+8k+4

So, we want b2=4ac

4k2=4k2+8k+4

0=8k+4

8k=−4

k=−84

k=−12