Question

find the value of kfor which the system of eqt. 9x-7y=0,3x+ky=0. have a non-zero solution

Answer 1

Hey mate !!

Here's the answer !!

There are some conditions through which we can find the value of " k " here.

We know that in a pair of linear equations,

a₁ / a₂ = b₁ / b₂ ≠ c₁ / c₂.

This means that, for the given two equations the solutions are not present.

Hence we know that,

a₁ = 9, a₂ = 3, b₁ = - 7, b₂ = k

So substituting in the formula we get,

=> 9 / 3 = - 7 / k

=> 3 / 1 = - 7 / k

Cross multiplying we get,

=> k * 3 = - 7 * 1

=> 3k = - 7

=> k = - 7 / 3 

Hence the value of k must be - 7 / 3 for the given condition and set of equations.

Hope my answer helps !!

Cheers !!