Question

find the value of kx+3y=k-3 ,12x + ky=k​

Answer 1

Answer:

Step-by-step explanation:

If k= 1/2 then a1=6 a2= 12; b1= 3 b2= 6; c1= -6+3=-3 c2=-6

therefore a1/a2=6/12= 1/2

b1/b2= 3/6= 1/2

c1/c2= -3/-6= 1/2

since, a1/a2= b1/b2= c1/c2

it has infinite solutions, hence 6 is wrong

k= -6

therefore, c1/c2= 9/-6= -3/2

a1/a2= -6/12= -1/2

b1/b1= 3/-6= -1/2=≠≠therefore, a1/a2= b1/b2≠ c1/c2

hence proved