Question

Find the value of log of √2√2√2√2√2√2 to base 2√2

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\rm ➪Value \: of \: log_{2}16-log_{2}$

Step-by-step explanation:

$\rm Value \: of \: log_{2}16-log_{2}2$

$=log_{2}2^{4}-log_{2}2=log$

$\rm →=4log_{2}2 - log_{2}$

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We know the logarithmic laws:

$\begin{gathered}i) log_{a}n^{m} = mlog_{a}n\\ii) log_{a}a = 1\end{gathered}$

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$\rm \begin{gathered}= 4-1\\=3\end{gathered}$

Therefore,

$\rm Value \: of \: log_{2}16-log_{2}2 = 3$

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