Math, asked by vishnu8115, 11 months ago

find the value of log tan 12'+log tan 18' + log tan 72' + log tan 78' with explanation

Answers

Answered by vishalkumar2806
0

 log(m)  +  log(n)  = log(mn) \\ tan(90 - x) = cot \: x \\  = log(tan12.tan18.tan72.tan78) \\  = log(tan12.tan18.cot18.cot12) \\  = log(1) = 0

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