Math, asked by anvitha6, 1 year ago

find the value of log45


Bhagatpriyanshu: log 45=log(9×5)=log9+log5 [log(ab)=loga+logb]=log32+log5 [logam=mloga]=2log3+log5=2×0.4771+0.699=0.9542+0.699=1.6532
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anvitha6: tq

Answers

Answered by kingsman05
5
1.65321251 this is the answer
log 45=log9×5=log9+log5         logab=loga+logb=log32+log5       logam=mloga=2log3+log5=2×0.4771+0.699=0.9542+0.699=1.6532

anvitha6: pls describe it
kingsman05: wait
kingsman05: log 45=log9×5=log9+log5         logab=loga+logb=log32+log5       logam=mloga=2log3+log5=2×0.4771+0.699=0.9542+0.699=1.6532
Answered by Anonymous
9
Hi @friend
=========
the value of log45 is 1.65321
if you want to know about logarithm than you need a log table or antilogarithm table
#see my answer:)

given
log45
= log9×log5
=log9+log5 ( because loga×logb= loga+logb)
=0.9542+0.6990
=1.6532
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