find the value of <AOQ
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Answer:
Angle AOQ is 64 degree
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Step-by-step explanation:
<PQO=90°(as it is a tangent)
<PQA=32°(given)
thus, <AQO=(90-32) °
=58°
OA=OQ(RADIUS)
THEN, <OQA=<QAO=58°
IN TRIANGLE AOQ, <OQA=<OAQ=58°
THUS, <AOQ=180°-(58+58) °
=(180-116) °
=64°
hope it helps
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