Question

Find the value of <BCD

Please Guys try to find the solution and send me

A humble request.....

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Answer 1

Step-by-step explanation:

(2x+5)+(3x+55)=180* (co-interior angle)

5x+60=180*

5x=180-60*

5x=120

x=14

Answer 2

Step-by-step explanation:

In Trapezium ABCD,

AD is parallel to BC,

Given that

Angle B=(2x+5)°

Angle C=(3x+55)°

We know that the sum of angles of the quadrilateral is 360°

We know that when the sides are parllel,

Angles are also equal.

Angle B=Angle D

Angle C=Angle A

(2x+5)+(3x+55)+(2x+5)+(3x+55)=360°

10x+120=360°

10x=360-120

10x=240

×=24

Angle B =Angle D=53°

Angle C=Angle A=91°