Question

if one of the zeros quadratic k-1 x2+ kx+ 1 is - 3 then the value of k​

Answer 1

$\huge\pink{\mathbb {Answer}}$

$(k - 1) {x}^{2} + kx + 1$

if -3 is a zero of this equation then it will satisfy the equation.

$(k - 1) {( - 3)}^{2} + k( - 3) + 1 = 0$

$(k - 1)9 - 3k + 1 = 0$

$9k - 9 - 3k + 1 = 0$

$6k - 8 = 0$

$6k = 8$

$k = \frac{8}{6}$

$k = \frac{4}{3}$

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