Question

find the value of 'm' and explain..?

Answer 1

$2 {m}^{3} - 7 {m}^{2} + 2m + 3 = 0 \\ \\ = > 2 {m}^{3} -( 2 {m}^{2} + 5 {m}^{2} ) + (5m - 3m) + 3 = 0 \\ \\ = > 2 {m}^{3} - 2 {m}^{2} - 5 {m}^{2} + 5m - 3m + 3 = 0 \\ \\ = > 2 {m}^{2} (m - 1) - 5m(m - 1) - 3(m - 1) = 0 \\ \\ = > (m - 1)(2 {m}^{2} - 5m - 3) = 0 \\ \\ = > (m - 1)(2 {m}^{2} - 6m + m - 3) = 0 \\ \\ = > (m - 1)[2m(m - 3) + 1(m - 3)]= 0 \\ \\ = > (m - 1)(m - 3)(2m + 1) = 0 \\ \\ Required \: value \: of \: m \: = 1 ,\: 3 \: and \: \frac{ - 1}{2}$

Answer 2

❤❤Holå mate❤❤

✨✨2m3−7m2+2m+3=0=>2m3−(2m2+5m2)+(5m−3m)+3=0=>2m3−2m2−5m2+5m−3m+3=0=>2m2(m−1)−5m(m−1)−3(m−1)=0=>(m−1)(2m2−5m−3)=0=>(m−1)(2m2−6m+m−3)=0=>(m−1)[2m(m−3)+1(m−3)]=0=>(m−1)(m−3)(2m+1)=0Requiredvalueofm=1,3and2−1​​


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