Question

Find the value of m for which 3m+4 ,6m-2 and 2m+6 are in ap

Answer 1

Hey,sup!

As per the question,

If they are in AP the common difference must be same.
So,
6m-2-(3m+4)=2m+6-(6m-2).
=>6m-2-3m-4=2m+6-6m+2.
=>3m-6=-4m+8.
=>3m+4m=8+6.
=>7m=14.
=>m=14/7.
=>m=2.

So they are in AP when m= 2.

Hope it helps.

Answer 2

if 3m+ 4,6m-2,2m+6 are in AP

the they must satisfy 2b= a+c

so 2(6m-2) = 3m+4+ 2m+6

= 12m -4 = 5m +10
7m= 14
m= 2

hope it helps