Question

find the value of m for which the equation (m+1)x^2(m+3)x+m+8=0 have equal roots​

Answer 1

Answer:

The given equation is (m+1)x

2

+2(m+3)x+(2m+3)=0

Here, a=(m+1),b=2(m+3) and c=(2m+3)

For equal roots,

Discriminant=0⇒b

2

−4ac=0

⇒[2(m+3)]

2

−4(m+1)(2m+3)=0

⇒[(m+3)]

2

−(m+1)(2m+3)=0

⇒m

2

+6m+9−2m

2

−5m−3=0

⇒−m

2

+m+6=0

⇒m

2

−m−6=0