Question

Find the value of 'm' from which the equation
(m+4)x^2+(m+1)x+1=0
has a real and equal roots.

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

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b^2-4ac

b^2=4ac

a= (m+1)^2

b= (m+1)

c= 1

(m+1)^2= 4(m+4)(1)

m^2+1+2m=4m+16

m^2-2m-15=0

m^2-5m+3m-15=0

m(m-5)+3(m-5)=0

m=-3 and 5

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