Chemistry, asked by ningthoujampate4381, 1 year ago

No of g of oxygen in 32.2g of Na2SO4.10H2O is?

Answers

Answered by Pragyan30
5

Answer:22.4g

Explanation:atomic mass of

Na2SO4.10H2O=2*23+32+4*16+20*1+10*16=46+32+64+20+160=322g

Moles of Na2SO4.10H2O=32.2/322=0.1 mole

Moles of O2=(4+10)*0.1=14*0.1=1.4 mole

No.of g of O2=1.4*16=22.4g

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