Find the value of m if polynomial p(x)=4x square-6x-m is exactly divisible by x-3.
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Using remainder theorem, we will solve this question;
Given that;
g(x) = x - 3
So, x = 3
p(x) = 4x² - 6x - m
p(3) = 4 (3)² - 6 * 3 - m
p(3) = 36 - 9 - m
p(3) = 27 - m
As it is exactly divisible, so p(x) = 0
⇒ 27 - m = 0
⇒ m = 27
Hence, the value of m is 27.
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